list extract file name

[Gilsornette]

Hello,

I'd like to extract (short) file names of a list comma text and to get all of them in a list box. [extract file name] is doing the job but only for one single name.
I cannot use [comma text extract] because the paths will be different so the indexes will change. I' m sure there is a simple way ...
Thank you

[senso]

in the listbox you have the option "hide path" and "hide extension" so you can connect the list directly without display their path.
Maybe it can do the trick?

[Gilsornette]

This is the simpliest way...
Thank you very much!